121-9k^2/11+3k

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Solution for 121-9k^2/11+3k equation: 


k in (-oo:+oo)

3*k-((9*k^2)/11)+121 = 0

(-9/11)*k^2+3*k+121 = 0

3*k-9/11*k^2+121 = 0

DELTA = 3^2-(-9/11*4*121)

DELTA = 405

DELTA > 0

k = (405^(1/2)-3)/(-9/11*2) or k = (-405^(1/2)-3)/(-9/11*2)

k = -11/18*(9*5^(1/2)-3) or k = -11/18*(-9*5^(1/2)-3)

k in { -11/18*(9*5^(1/2)-3), -11/18*(-9*5^(1/2)-3) }

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